Degree Wood

If a 10g bullet is fired horizontally into a block of wood that is 2kg and the wood is hanging from a rope?

that is 1m long. When the bullet embeds in the wood, the block swings to a 53 degree angle. How much PE does the block wood have when it reaches 53 degrees? How fast was the block bullet traveling after the collision?

First off it is a 3,4,5 triangles

When theta is 53 degrees the Y axis becomes .6meter

since PE=mgh
PE=2.01kg(10m/s^2)(.4m)
8 Jewels

KE= 1/2mv^2

PE gained= KE lost

8=1/2(.01kg)v^2

1600=v^2

v=40m/s

Morningwood - Nth Degree

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